-(-3)^3-(-2)-2^2-(-k-3)=-4^2-(3k-4)

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Solution for -(-3)^3-(-2)-2^2-(-k-3)=-4^2-(3k-4) equation: 



-(-3)^3-(-2)-2^2-(-k-3)=-4^2-(3k-4)

We move all terms to the left:

-(-3)^3-(-2)-2^2-(-k-3)-(-4^2-(3k-4))=0

We add all the numbers together, and all the variables

-(-1k-3)-(-4^2-(3k-4))-(-3)^3-(-2)-2^2=0

We add all the numbers together, and all the variables

-(-1k-3)-(-4^2-(3k-4))+25=0

We get rid of parentheses

1k-(-4^2-(3k-4))+3+25=0



We calculate terms in parentheses: -(-4^2-(3k-4)), so:

-4^2-(3k-4)

determiningTheFunctionDomain
-(3k-4)-4^2

We add all the numbers together, and all the variables

-(3k-4)-16

We get rid of parentheses

-3k+4-16

We add all the numbers together, and all the variables

-3k-12

Back to the equation:

-(-3k-12)



We add all the numbers together, and all the variables

k-(-3k-12)+28=0

We get rid of parentheses

k+3k+12+28=0

We add all the numbers together, and all the variables

4k+40=0

We move all terms containing k to the left, all other terms to the right

4k=-40

k=-40/4

k=-10

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